A triangle ABC has a line DE drawn parallel to its base BC, cutting side AB at D and side AC at E. Drag the round handle up or down to slide the parallel line, or drag any triangle vertex. Because DE is parallel to BC, it splits the two sides in equal ratios: AD over DB equals AE over EC. The cut-off segment DE is also the same fraction of BC as AD is of AB. The segment lengths and the equal ratios are shown live on the figure and below it. An info button opens a drawer explaining the theorem.
DE ∥ BC ⟹ AD / DB = AE / EC
Slide the purple handle to move the parallel line. The two ratios stay equal at every height.